What is (\partial)/(\partial x)(7+x^2+y^2) ?

The answer to (\partial)/(\partial x)(7+x^2+y^2) is 2x

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(\partial)/(\partial x)(7+x^2+y^2)

\frac{\partial}{\partial x} (7 + x^{2} + y^{2})

2 x

Solution steps

\frac{\partial}{\partial x} (7 + x^{2} + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (7) + \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (7) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 0 + 2 x + 0

Simplify

= 2 x

f (x) = x + \frac{9}{x}, (9, 10)

\int cos^{3} (t) - sin^{2} (t) cos (t) d t

y = x^{2} - 5 x - 6

f (x) = \frac{( x + 9 )}{x ^{2} - 7 x + 1}

g (x) = \frac{7}{x}

What is (\partial)/(\partial x)(7+x^2+y^2) ?
The answer to (\partial)/(\partial x)(7+x^2+y^2) is 2x