What is the integral from 0 to 1 of 7tcosh(t) ?

The integral from 0 to 1 of 7tcosh(t) is 7(-1/e+1)

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integral from 0 to 1 of 7tcosh(t)

\int_{0}^{1} 7 t cosh (t) d t

7 (- \frac{1}{e} + 1)

Decimal

4.42484 \dots

Solution steps

\int_{0}^{1} 7 t cosh (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int_{0}^{1} t cosh (t) d t

Apply Integration By Parts

: [t sinh (t) - \int sinh (t) d t]_{0}^{1}

= 7 [t sinh (t) - \int sinh (t) d t]_{0}^{1}

\int sinh (t) d t = cosh (t)

= 7 [t sinh (t) - cosh (t)]_{0}^{1}

Compute the boundaries:

- \frac{1}{e} + 1

= 7 (- \frac{1}{e} + 1)

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What is the integral from 0 to 1 of 7tcosh(t) ?
The integral from 0 to 1 of 7tcosh(t) is 7(-1/e+1)