What is the integral from 6 to 2 of x^3 ?

The integral from 6 to 2 of x^3 is -320

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integral from 6 to 2 of x^3

\int_{6}^{2} x^{3} d x

- 320

Solution steps

\int_{6}^{2} x^{3} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{2}^{6} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{2}^{6}

= - [\frac{x ^{4}}{4}]_{2}^{6}

Compute the boundaries:

320

= - 320

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What is the integral from 6 to 2 of x^3 ?
The integral from 6 to 2 of x^3 is -320