What is (\partial}{\partial z}(\frac{z^2)/y) ?

The answer to (\partial}{\partial z}(\frac{z^2)/y) is (2z)/y

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(\partial}{\partial z}(\frac{z^2)/y)

\frac{\partial}{\partial z} (\frac{z ^{2}}{y})

\frac{2 z}{y}

Solution steps

\frac{\partial}{\partial z} (\frac{z ^{2}}{y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{y} \frac{\partial}{\partial z} (z^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{y} \cdot 2 z^{2 - 1}

Simplify

\frac{1}{y} \cdot 2 z^{2 - 1} : \frac{2 z}{y}

= \frac{2 z}{y}

\frac{d}{d x} (x^{2} - cos (2 x))

(12 + x^{2}) y^{^{'}} - 2 x y = 0

x \to 0 + lim (x^{x})

\frac{\partial}{\partial x} (x^{6} - 8 x^{3} y)

\int λ e^{- λ t} d t

What is (\partial}{\partial z}(\frac{z^2)/y) ?
The answer to (\partial}{\partial z}(\frac{z^2)/y) is (2z)/y