What is the integral from 0 to 1/5 of 4x ?

The integral from 0 to 1/5 of 4x is 2/25

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integral from 0 to 1/5 of 4x

\int_{0}^{\frac{1}{5}} 4 x d x

\frac{2}{25}

Decimal Notation

0.08

Solution steps

\int_{0}^{\frac{1}{5}} 4 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{\frac{1}{5}} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{\frac{1}{5}}

= 4 [\frac{x ^{2}}{2}]_{0}^{\frac{1}{5}}

Compute the boundaries:

\frac{1}{50}

= 4 \cdot \frac{1}{50}

Simplify

= \frac{2}{25}

\int_{1}^{2} x^{2} + 4 d x

\int_{3}^{4} \frac{1}{2 - 5 t} d t

\int_{0}^{2} (3 x + 1) e^{2 x} d x

\int_{1}^{4} (- 5 - x^{2}) d x

\int_{0}^{x} 1 d y

What is the integral from 0 to 1/5 of 4x ?
The integral from 0 to 1/5 of 4x is 2/25