What is area x=0,y=0,y=sqrt((-x^2+8)/9) ?

The answer to area x=0,y=0,y=sqrt((-x^2+8)/9) is (4pi)/3

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area x=0,y=0,y=sqrt((-x^2+8)/9)

area

x = 0, y = 0, y = \frac{- x ^{2} + 8}{9}

\frac{4 π}{3}

Decimal Notation

4.18879 \dots

Solution steps

Apply the area formula:

\int_{- 22}^{22} \frac{1}{3} - x^{2} + 8 d x

Solve

\int_{- 22}^{22} \frac{1}{3} - x^{2} + 8 d x : \frac{4 π}{3}

The area is:

= \frac{4 π}{3}

θ \to 0 lim (\frac{θ}{sin ( θ )})

\frac{d y}{d x} + \frac{y}{x} = x^{2} y^{2}

\int \frac{4 x - 7}{2 x ^{4}} d x

\frac{\partial}{\partial x} ((x - y) (1 - x y))

What is area x=0,y=0,y=sqrt((-x^2+8)/9) ?
The answer to area x=0,y=0,y=sqrt((-x^2+8)/9) is (4pi)/3