What is the integral from 0 to 1 of 2r ?

The integral from 0 to 1 of 2r is 1

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integral from 0 to 1 of 2r

\int_{0}^{1} 2 r d r

1

Solution steps

\int_{0}^{1} 2 r d r

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{1} r d r

Apply the Power Rule

: [\frac{r ^{2}}{2}]_{0}^{1}

= 2 [\frac{r ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= 2 \cdot \frac{1}{2}

Simplify

= 1

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