What is the derivative of x^2+x-5 ?

The derivative of x^2+x-5 is 2x+1

What is the first derivative of x^2+x-5 ?

The first derivative of x^2+x-5 is 2x+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

x^{2} + x - 5

2 x + 1

Solution steps

\frac{d}{d x} (x^{2} + x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (5) = 0

= 2 x + 1 - 0

Simplify

= 2 x + 1

\int_{1}^{2} \frac{1}{x} d x

\frac{\partial}{\partial x} (3 x yz)

n = 1 \sum \infty 2^{n} (n!)^{2}

\int_{1}^{3} (4 x^{3} - 8 x + 1) d x

\frac{d}{d x} (\frac{4}{x} + x^{2})

What is the derivative of x^2+x-5 ?
The derivative of x^2+x-5 is 2x+1
What is the first derivative of x^2+x-5 ?
The first derivative of x^2+x-5 is 2x+1