What is the integral from 0 to 2 of 1/25 y ?

The integral from 0 to 2 of 1/25 y is 2/25

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integral from 0 to 2 of 1/25 y

\int_{0}^{2} \frac{1}{25} y d y

\frac{2}{25}

Solution steps

\int_{0}^{2} \frac{1}{25} y d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{25} \cdot \int_{0}^{2} y d y

Apply the Power Rule

: [\frac{y ^{2}}{2}]_{0}^{2}

= \frac{1}{25} [\frac{y ^{2}}{2}]_{0}^{2}

Compute the boundaries:

2

= \frac{1}{25} \cdot 2

Simplify

= \frac{2}{25}

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What is the integral from 0 to 2 of 1/25 y ?
The integral from 0 to 2 of 1/25 y is 2/25