What is the integral from 0 to infinity of 18e^{-2x} ?

The integral from 0 to infinity of 18e^{-2x} is 9

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integral from 0 to infinity of 18e^{-2x}

\int_{0}^{\infty} 18 e^{- 2 x} d x

9

Solution steps

\int_{0}^{\infty} 18 e^{- 2 x} d x

Compute the indefinite integral:

\int 18 e^{- 2 x} d x = - 9 e^{- 2 x} + C

Compute the boundaries:

\int_{0}^{\infty} 18 e^{- 2 x} d x = 0 - (- 9)

= 0 - (- 9)

Simplify

= 9

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What is the integral from 0 to infinity of 18e^{-2x} ?
The integral from 0 to infinity of 18e^{-2x} is 9