What is the integral from-1 to 6 of 3x ?

The integral from-1 to 6 of 3x is 105/2

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integral from-1 to 6 of 3x

\int_{- 1}^{6} 3 x d x

\frac{105}{2}

Solution steps

\int_{- 1}^{6} 3 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{- 1}^{6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{- 1}^{6}

= 3 [\frac{x ^{2}}{2}]_{- 1}^{6}

Compute the boundaries:

\frac{35}{2}

= 3 \cdot \frac{35}{2}

Simplify

= \frac{105}{2}

\int_{- 3}^{3} \frac{x}{1 + x ^{2}} d x

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\int_{0}^{π} e^{- \frac{t}{2}} d t

\int_{0}^{2} x^{2} + k x + 1 d x

\int_{0}^{1} \frac{x ^{2} + x}{x} d x

What is the integral from-1 to 6 of 3x ?
The integral from-1 to 6 of 3x is 105/2