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Popular >

integral from 0 to 2 of (6y^2-2y)

Solution

\int_{0}^{2} (6 y^{2} - 2 y) d y

Solution

12

Solution steps

\int_{0}^{2} 6 y^{2} - 2 y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 6 y^{2} d y - \int_{0}^{2} 2 y d y

\int_{0}^{2} 6 y^{2} d y = 16

\int_{0}^{2} 2 y d y = 4

= 16 - 4

Simplify

= 12

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (6y^2-2y) ?
The integral from 0 to 2 of (6y^2-2y) is 12