What is the integral from a to b of 1/(sqrt(x)) ?

The integral from a to b of 1/(sqrt(x)) is 2sqrt(b)-2sqrt(a)

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integral from a to b of 1/(sqrt(x))

\int_{a}^{b} \frac{1}{x} d x

2 b - 2 a

Solution steps

\int_{a}^{b} \frac{1}{x} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{a}^{b}

= [2 x^{\frac{1}{2}}]_{a}^{b}

Apply radical rule:

= [2 x]_{a}^{b}

Compute the boundaries:

2 b - 2 a

= 2 b - 2 a

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What is the integral from a to b of 1/(sqrt(x)) ?
The integral from a to b of 1/(sqrt(x)) is 2sqrt(b)-2sqrt(a)