What is the integral from 0 to infinity of 4x ?

The integral from 0 to infinity of 4x is diverges

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integral from 0 to infinity of 4x

\int_{0}^{\infty} 4 x d x

diverges

Solution steps

\int_{0}^{\infty} 4 x d x

Compute the indefinite integral:

\int 4 x d x = 2 x^{2} + C

Compute the boundaries:

\int_{0}^{\infty} 4 x d x =

diverges

= diverges

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\int_{0}^{1} (- y - \frac{1}{2} e^{y}) d y

\int_{- 1}^{3} 1 + (2 y + 3)^{2} d y

\int_{0}^{b} (a - a \frac{x}{b}) d x

\int_{- 1}^{1} x \frac{3}{4} (1 - x^{2}) d x

What is the integral from 0 to infinity of 4x ?
The integral from 0 to infinity of 4x is diverges