What is the tangent of y= 1/(5+2x),(2, 1/9) ?

The tangent of y= 1/(5+2x),(2, 1/9) is y=-2/81 x+13/81

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tangent of y= 1/(5+2x),(2, 1/9)

tangent of

y = \frac{1}{5 + 2 x}, (2, \frac{1}{9})

y = - \frac{2}{81} x + \frac{13}{81}

Solution steps

Find the slope of

y = \frac{1}{5 + 2 x} : \frac{d y}{d x} = - \frac{2}{( 5 + 2 x ) ^{2}}

Compute the slope of

y = \frac{1}{5 + 2 x}

(2, \frac{1}{9}) : m = - \frac{2}{81}

Find the line with slope m=

- \frac{2}{81}

and passing through

(2, \frac{1}{9}) : y = - \frac{2}{81} x + \frac{13}{81}

y = - \frac{2}{81} x + \frac{13}{81}

\frac{y ^{^{'}} - e ^{- t} + 4}{y} = - 4, y (0) = - 4

\int x^{3} x^{2} + 45 d x

(2 y + 1) d x + (\frac{x ^{2} - y}{x}) d y = 0

\int_{0}^{2} (x (64 - (x + 3)^{3})) d x

\frac{d}{d x} ((x^{2} - x)^{3})

What is the tangent of y= 1/(5+2x),(2, 1/9) ?
The tangent of y= 1/(5+2x),(2, 1/9) is y=-2/81 x+13/81