What is the limit as x approaches 0 of sqrt(1+2x) ?

The limit as x approaches 0 of sqrt(1+2x) is 1

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limit as x approaches 0 of sqrt(1+2x)

x \to 0 lim (1 + 2 x)

1

Solution steps

x \to 0 lim (1 + 2 x)

Plug in the value

x = 0

= 1 + 2 \cdot 0

Simplify

= 1

\frac{\partial}{\partial x} (x e^{x^{2} y^{2}})

x \to 1 lim (b + \frac{1}{x - 1})

y = 4 x, y = \frac{4}{x}, x = 4

\frac{1}{s ( s ^{2} + 6 s + 13 )}

What is the limit as x approaches 0 of sqrt(1+2x) ?
The limit as x approaches 0 of sqrt(1+2x) is 1