What is the derivative of 1+tan^2(x) ?

The derivative of 1+tan^2(x) is 2sec^2(x)tan(x)

What is the first derivative of 1+tan^2(x) ?

The first derivative of 1+tan^2(x) is 2sec^2(x)tan(x)

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derivative of

1 + tan^{2} (x)

2 sec^{2} (x) tan (x)

Solution steps

\frac{d}{d x} (1 + tan^{2} (x))

Simplify

1 + tan^{2} (x) : sec^{2} (x)

= \frac{d}{d x} (sec^{2} (x))

Apply the chain rule:

2 sec (x) \frac{d}{d x} (sec (x))

= 2 sec (x) \frac{d}{d x} (sec (x))

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

= 2 sec (x) sec (x) tan (x)

Simplify

2 sec (x) sec (x) tan (x) : 2 sec^{2} (x) tan (x)

= 2 sec^{2} (x) tan (x)

\int (1 - csc (x) cot (x)) d x

\frac{d}{d x} (sin (2 x^{3} - 3))

x^{2} + 6 x

\frac{d}{d x} (e^{2 x} e^{3 x} e^{4 x})

f^{^{'}} (x) = x - 3 + π x^{2} - 2

What is the derivative of 1+tan^2(x) ?
The derivative of 1+tan^2(x) is 2sec^2(x)tan(x)
What is the first derivative of 1+tan^2(x) ?
The first derivative of 1+tan^2(x) is 2sec^2(x)tan(x)