What is the derivative of e^{2x}e^{3x}e^{4x} ?

The derivative of e^{2x}e^{3x}e^{4x} is e^{9x}*9

What is the first derivative of e^{2x}e^{3x}e^{4x} ?

The first derivative of e^{2x}e^{3x}e^{4x} is e^{9x}*9

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\frac{d}{d x} (e^{2 x} e^{3 x} e^{4 x})

e^{9 x} \cdot 9

Solution steps

\frac{d}{d x} (e^{2 x} e^{3 x} e^{4 x})

Simplify

e^{2 x} e^{3 x} e^{4 x} : e^{9 x}

= \frac{d}{d x} (e^{9 x})

Apply the chain rule:

e^{9 x} \frac{d}{d x} (9 x)

= e^{9 x} \frac{d}{d x} (9 x)

\frac{d}{d x} (9 x) = 9

= e^{9 x} \cdot 9

f^{^{'}} (x) = x - 3 + π x^{2} - 2

x \to 1 lim (5 x^{2} + 2)

y = x + 1, y = 2 - x + 1, y = 1

x^{2} y^{^{'}} + x y = 1, y (1) = 2

22 e^{x^{2}} x

What is the derivative of e^{2x}e^{3x}e^{4x} ?
The derivative of e^{2x}e^{3x}e^{4x} is e^{9x}*9
What is the first derivative of e^{2x}e^{3x}e^{4x} ?
The first derivative of e^{2x}e^{3x}e^{4x} is e^{9x}*9