What is the derivative of sin(2x^3-3) ?

The derivative of sin(2x^3-3) is cos(2x^3-3)*6x^2

What is the first derivative of sin(2x^3-3) ?

The first derivative of sin(2x^3-3) is cos(2x^3-3)*6x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (sin (2 x^{3} - 3))

cos (2 x^{3} - 3) \cdot 6 x^{2}

Solution steps

\frac{d}{d x} (sin (2 x^{3} - 3))

Apply the chain rule:

cos (2 x^{3} - 3) \frac{d}{d x} (2 x^{3} - 3)

= cos (2 x^{3} - 3) \frac{d}{d x} (2 x^{3} - 3)

\frac{d}{d x} (2 x^{3} - 3) = 6 x^{2}

= cos (2 x^{3} - 3) \cdot 6 x^{2}

x^{2} + 6 x

\frac{d}{d x} (e^{2 x} e^{3 x} e^{4 x})

f^{^{'}} (x) = x - 3 + π x^{2} - 2

x \to 1 lim (5 x^{2} + 2)

y = x + 1, y = 2 - x + 1, y = 1

What is the derivative of sin(2x^3-3) ?
The derivative of sin(2x^3-3) is cos(2x^3-3)*6x^2
What is the first derivative of sin(2x^3-3) ?
The first derivative of sin(2x^3-3) is cos(2x^3-3)*6x^2