Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Cauchy's Convergence Condition:diverges

Popular Examples

sum from n=1 to infinity of 3^{-4n}sum from n=1 to infinity of (n^8)/(8^n)sum from n=1 to infinity of (e^n)/(n^6)sum from n=0 to infinity of (2^n)/nsum from i=1 to infinity of 2(4/i)^3+9

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of 9/n ?

    The sum from n=1 to infinity of 9/n is diverges