What is the limit as x approaches 3 of 5/(x^2-9) ?

The limit as x approaches 3 of 5/(x^2-9) is diverges

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limit as x approaches 3 of 5/(x^2-9)

x \to 3 lim (\frac{5}{x ^{2} - 9})

diverges

Solution steps

x \to 3 lim (\frac{5}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{5}{x ^{2} - 9}) = \infty

x \to 3 - lim (\frac{5}{x ^{2} - 9}) = - \infty

= diverges

x \to 0 + lim (x^{4 x})

\frac{d y}{d x} = \frac{1}{5} x

f (x) = x^{2} - 4, at x = 3

\int e^{4 θ} sin (5 θ) d θ

f (x) = 3 x^{2}, g (x) = - 3 x + 6, [- 4, 2]

What is the limit as x approaches 3 of 5/(x^2-9) ?
The limit as x approaches 3 of 5/(x^2-9) is diverges