What is (\partial)/(\partial x)(cos(x/2)) ?

The answer to (\partial)/(\partial x)(cos(x/2)) is -sin(x/2) 1/2

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(\partial)/(\partial x)(cos(x/2))

\frac{\partial}{\partial x} (cos (\frac{x}{2}))

- sin (\frac{x}{2}) \frac{1}{2}

Solution steps

\frac{\partial}{\partial x} (cos (\frac{x}{2}))

Apply the chain rule:

- sin (\frac{x}{2}) \frac{\partial}{\partial x} (\frac{x}{2})

= - sin (\frac{x}{2}) \frac{\partial}{\partial x} (\frac{x}{2})

\frac{\partial}{\partial x} (\frac{x}{2}) = \frac{1}{2}

= - sin (\frac{x}{2}) \frac{1}{2}

x \to 7 lim (2 x^{- 1})

f (x) = \frac{x ^{12}}{x ^{2}}

\frac{8 x}{x ^{2} + 1}

\frac{d}{d x} (2 (x^{2} + y^{2})^{2})

\int cos (3 x) cos (9 x) d x

What is (\partial)/(\partial x)(cos(x/2)) ?
The answer to (\partial)/(\partial x)(cos(x/2)) is -sin(x/2) 1/2