What is the sum from n=1 to infinity of 6/n-6/(n^2) ?

The sum from n=1 to infinity of 6/n-6/(n^2) is diverges

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sum from n=1 to infinity of 6/n-6/(n^2)

n = 1 \sum \infty \frac{6}{n} - \frac{6}{n ^{2}}

diverges

Solution steps

n = 1 \sum \infty \frac{6}{n} - \frac{6}{n ^{2}}

Apply Series Integral Test:

diverges

= diverges

n = 1 \sum \infty 30 (0.1)^{n}

n = 1 \sum \infty \frac{8}{n} + 3^{- n}

n = 1 \sum \infty \frac{1}{( 9 n ) ^{9}}

k = 2 \sum \infty (- 0.15)^{k}

n = 5 \sum \infty \frac{e ^{n}}{5 ^{n}}

What is the sum from n=1 to infinity of 6/n-6/(n^2) ?
The sum from n=1 to infinity of 6/n-6/(n^2) is diverges