What is the derivative of (9x/(x+4)) ?

The derivative of (9x/(x+4)) is (36)/((x+4)^2)

What is the first derivative of (9x/(x+4)) ?

The first derivative of (9x/(x+4)) is (36)/((x+4)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{9 x}{x + 4})

\frac{36}{( x + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{9 x}{x + 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{x}{x + 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 9 \cdot \frac{\frac{d x}{d x} ( x + 4 ) - \frac{d}{d x} ( x + 4 ) x}{( x + 4 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x + 4) = 1

= 9 \cdot \frac{1 \cdot ( x + 4 ) - 1 \cdot x}{( x + 4 ) ^{2}}

Simplify

9 \cdot \frac{1 \cdot ( x + 4 ) - 1 \cdot x}{( x + 4 ) ^{2}} : \frac{36}{( x + 4 ) ^{2}}

= \frac{36}{( x + 4 ) ^{2}}

\frac{d y}{d x} = 4 y^{2}

\frac{s + 3}{( s + 2 ) ( s + 1 )}

\int - \frac{2}{x ^{\frac{1}{2}}} d x

\frac{\partial}{\partial x} (cos (x - y) - x e^{y})

f (x) = 3 x - x^{2}

What is the derivative of (9x/(x+4)) ?
The derivative of (9x/(x+4)) is (36)/((x+4)^2)
What is the first derivative of (9x/(x+4)) ?
The first derivative of (9x/(x+4)) is (36)/((x+4)^2)