What is the sum from n=1 to infinity of (1+(1/n))^n ?

The sum from n=1 to infinity of (1+(1/n))^n is diverges

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sum from n=1 to infinity of (1+(1/n))^n

n = 1 \sum \infty (1 + (\frac{1}{n}))^{n}

diverges

Solution steps

n = 1 \sum \infty (1 + \frac{1}{n})^{n}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty e^{- \frac{n}{6}}

n = 1 \sum \infty \frac{n - 3}{2 ^{n}}

n = 4 \sum \infty \frac{2}{5 n ^{3}}

n = 0 \sum \infty 1 + \frac{( - 1 ) ^{n}}{n}

k = 1 \sum \infty [(k) (\frac{1}{2})^{k}]

What is the sum from n=1 to infinity of (1+(1/n))^n ?
The sum from n=1 to infinity of (1+(1/n))^n is diverges