What is the sum from n=2 to infinity of 1/(2^n+1) ?

The sum from n=2 to infinity of 1/(2^n+1) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=2 to infinity of 1/(2^n+1)

n = 2 \sum \infty \frac{1}{2 ^{n} + 1}

converges

Solution steps

n = 2 \sum \infty \frac{1}{2 ^{n} + 1}

Apply Series Ratio Test:

converges

= converges

n = 0 \sum \infty n^{3} (- 1)^{n}

n = 1 \sum \infty \frac{5}{e ^{n}}

n = 1 \sum \infty (sin (400))^{n}

n = 0 \sum \infty \frac{n !}{n + 1}

n = 1 \sum \infty \frac{1}{7 n ^{3} + 3}

What is the sum from n=2 to infinity of 1/(2^n+1) ?
The sum from n=2 to infinity of 1/(2^n+1) is converges