What is the first (4cos(t))^' ?

The first (4cos(t))^' is -4sin(t)

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(4cos(t))^'

(4 cos (t))^{^{'}}

- 4 sin (t)

Solution steps

(4 cos (t))^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 (cos (t))^{^{'}}

Apply the common derivative:

(cos (t))^{'} = - sin (t)

= 4 (- sin (t))

Simplify

= - 4 sin (t)

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