What is the derivative of f(x)=(cos(x))/(1+asin(x)) ?

The derivative of f(x)=(cos(x))/(1+asin(x)) is (-sin(x)(1+asin(x))-acos^2(x))/((1+asin(x))^2)

What is the first derivative of f(x)=(cos(x))/(1+asin(x)) ?

The first derivative of f(x)=(cos(x))/(1+asin(x)) is (-sin(x)(1+asin(x))-acos^2(x))/((1+asin(x))^2)

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derivative of

f (x) = \frac{cos ( x )}{1 + a sin ( x )}

\frac{- sin ( x ) ( 1 + a sin ( x ) ) - a cos ^{2} ( x )}{( 1 + a sin ( x ) ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{cos ( x )}{1 + a sin ( x )})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( cos ( x ) ) ( 1 + a sin ( x ) ) - \frac{d}{d x} ( 1 + a sin ( x ) ) cos ( x )}{( 1 + a sin ( x ) ) ^{2}}

\frac{d}{d x} (cos (x)) = - sin (x)

\frac{d}{d x} (1 + a sin (x)) = a cos (x)

= \frac{( - sin ( x ) ) ( 1 + a sin ( x ) ) - a cos ( x ) cos ( x )}{( 1 + a sin ( x ) ) ^{2}}

Simplify

\frac{( - sin ( x ) ) ( 1 + a sin ( x ) ) - a cos ( x ) cos ( x )}{( 1 + a sin ( x ) ) ^{2}} : \frac{- sin ( x ) ( 1 + a sin ( x ) ) - a cos ^{2} ( x )}{( 1 + a sin ( x ) ) ^{2}}

= \frac{- sin ( x ) ( 1 + a sin ( x ) ) - a cos ^{2} ( x )}{( 1 + a sin ( x ) ) ^{2}}

y = sin (ln (x))

\int_{0}^{1} x^{2} d x

\frac{\partial}{\partial x} (x e^{x y} cos (2 x) - 3)

\frac{d x}{d t} = cot (x) cos (t)

(x + 1) e^{x}

What is the derivative of f(x)=(cos(x))/(1+asin(x)) ?
The derivative of f(x)=(cos(x))/(1+asin(x)) is (-sin(x)(1+asin(x))-acos^2(x))/((1+asin(x))^2)
What is the first derivative of f(x)=(cos(x))/(1+asin(x)) ?
The first derivative of f(x)=(cos(x))/(1+asin(x)) is (-sin(x)(1+asin(x))-acos^2(x))/((1+asin(x))^2)