What is the integral from-2 to 3 of (8x^3+3x-1) ?

The integral from-2 to 3 of (8x^3+3x-1) is 265/2

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integral from-2 to 3 of (8x^3+3x-1)

\int_{- 2}^{3} (8 x^{3} + 3 x - 1) d x

\frac{265}{2}

Decimal Notation

132.5

Solution steps

\int_{- 2}^{3} 8 x^{3} + 3 x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{3} 8 x^{3} d x + \int_{- 2}^{3} 3 x d x - \int_{- 2}^{3} 1 d x

\int_{- 2}^{3} 8 x^{3} d x = 130

\int_{- 2}^{3} 3 x d x = \frac{15}{2}

\int_{- 2}^{3} 1 d x = 5

= 130 + \frac{15}{2} - 5

Simplify

130 + \frac{15}{2} - 5 : \frac{265}{2}

= \frac{265}{2}

\int e^{x} - \frac{1}{2} y^{2} d x

- 2 x^{\frac{3}{2}}

\frac{d y}{d x} = \frac{1 - x - y}{x + y}

y = 9 x^{3}

\frac{\partial}{\partial x} (2 y + x^{2} cos (t))

What is the integral from-2 to 3 of (8x^3+3x-1) ?
The integral from-2 to 3 of (8x^3+3x-1) is 265/2