What is the derivative of y=9x^3 ?

The derivative of y=9x^3 is 27x^2

What is the first derivative of y=9x^3 ?

The first derivative of y=9x^3 is 27x^2

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derivative of

y = 9 x^{3}

27 x^{2}

Solution steps

\frac{d}{d x} (9 x^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 \cdot 3 x^{3 - 1}

Simplify

= 27 x^{2}

\frac{\partial}{\partial x} (2 y + x^{2} cos (t))

y^{^{'}} = \frac{x - 4}{y - 6}

(4, 5), (1, 2)

x \to 0 lim (\frac{∣ 2 x ∣}{x})

\frac{\partial}{\partial x} (\frac{1}{t ^{2} + 1})

What is the derivative of y=9x^3 ?
The derivative of y=9x^3 is 27x^2
What is the first derivative of y=9x^3 ?
The first derivative of y=9x^3 is 27x^2