What is the solution for 2(dy}{dx}=\frac{y(x+1))/x ?

The solution for 2(dy}{dx}=\frac{y(x+1))/x is y=e^{(x+ln(x)+c_{1})/2}

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2(dy}{dx}=\frac{y(x+1))/x

2 \frac{d y}{d x} = \frac{y ( x + 1 )}{x}

y = e^{\frac{x + l n ( x ) + c _{1}}{2}}

Solution steps

2 \frac{d y}{d x} = \frac{y ( x + 1 )}{x}

Solve separable ODE:

y = e^{\frac{x + l n ( x ) + c _{1}}{2}}

y = e^{\frac{x + l n ( x ) + c _{1}}{2}}

x - 1 \frac{d y}{d x} = \frac{x}{y}

\frac{d y}{d x} = \frac{y - 1}{x + 3}

e^{2 x - y} d x + e^{y - 2 x} d y = 0

\frac{d y}{d x} = - 2 x y^{4}

(y + y cos (x) y) d x + (x + x cos (x) y) d y = 0

What is the solution for 2(dy}{dx}=\frac{y(x+1))/x ?
The solution for 2(dy}{dx}=\frac{y(x+1))/x is y=e^{(x+ln(x)+c_{1})/2}