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Popular >

y^'=-2xy^2

Solution

y^{^{'}} = - 2 x y^{2}

Solution

y = - \frac{1}{- x ^{2} + c _{1}}

Solution steps

y^{'} (x) = - 2 x y^{2}

Solve separable ODE:

y = - \frac{1}{- x ^{2} + c _{1}}

y = - \frac{1}{- x ^{2} + c _{1}}

Popular Examples

y^'=(1+y^2)/(xy(1+x^2))

y^{^{'}} = \frac{1 + y ^{2}}{x y ( 1 + x ^{2} )}

\frac{d x}{d t} = a - b x

y^{^{'}} = \frac{y + 1}{x}

(dy)/(dx)=(y^2+xy^2)/(x^2y-x^2)

\frac{d y}{d x} = \frac{y ^{2} + x y ^{2}}{x ^{2} y - x ^{2}}

3e^xtan(y)dx+(1-e^x)sec^2(y)dy=0

3 e^{x} tan (y) d x + (1 - e^{x}) sec^{2} (y) d y = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=-2xy^2 ?
The solution for y^'=-2xy^2 is y=-1/(-x^2+c_{1)}