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Popular >

y^'=(y+1)/x

Solution

y^{^{'}} = \frac{y + 1}{x}

Solution

y = c_{1} x - 1

Solution steps

y^{'} (x) = \frac{y + 1}{x}

Solve separable ODE:

y = c_{1} x - 1

y = c_{1} x - 1

Popular Examples

(dy)/(dx)=(y^2+xy^2)/(x^2y-x^2)

\frac{d y}{d x} = \frac{y ^{2} + x y ^{2}}{x ^{2} y - x ^{2}}

3e^xtan(y)dx+(1-e^x)sec^2(y)dy=0

3 e^{x} tan (y) d x + (1 - e^{x}) sec^{2} (y) d y = 0

(dy)/(dx)=ye^{3x}

\frac{d y}{d x} = y e^{3 x}

(dy)/(dx)=y^2-3y+2

\frac{d y}{d x} = y^{2} - 3 y + 2

(1+t^2)(dy)/(dt)=1+y^2

(1 + t^{2}) \frac{d y}{d t} = 1 + y^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'=(y+1)/x ?
The solution for y^'=(y+1)/x is y=c_{1}x-1