en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=e^{2x+3y}

Solution

y^{^{'}} = e^{2 x + 3 y}

Solution

y = - \frac{ln ( - \frac{3}{2} e ^{2 x} - c _{1} )}{3}

Solution steps

y^{'} (x) = e^{2 x + 3 y}

Solve separable ODE:

y = - \frac{ln ( - \frac{3}{2} e ^{2 x} - c _{1} )}{3}

y = - \frac{ln ( - \frac{3}{2} e ^{2 x} - c _{1} )}{3}

Popular Examples

(dy)/(dx)=-3/4 x^4y^2

\frac{d y}{d x} = - \frac{3}{4} x^{4} y^{2}

y^'=12xy-2x,y(0)=17

y^{^{'}} = 12 x y - 2 x, y (0) = 17

(dy)/(dt)+2y=3,y(0)=1

\frac{d y}{d t} + 2 y = 3, y (0) = 1

(dy)/(dx)+ycos(x)=6cos(x)

\frac{d y}{d x} + y cos (x) = 6 cos (x)

e^xdx-(1+e^x)ydy=0

e^{x} d x - (1 + e^{x}) y d y = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{2x+3y} ?
The solution for y^'=e^{2x+3y} is y=-(ln(-3/2 e^{2x}-c_{1}))/3