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Popular >

y^'=a(1-y)

Solution

y^{^{'}} = a (1 - y)

Solution

y = - e^{- a t - c_{1}} + 1

Solution steps

y^{'} (t) = a (1 - y)

Solve separable ODE:

y = - e^{- a t - c_{1}} + 1

y = - e^{- a t - c_{1}} + 1

Popular Examples

y^'=2x*cosh^2(y)

y^{^{'}} = 2 x \cdot cosh^{2} (y)

(dy)/(dx)=2xy^2,y=-1,x=1

\frac{d y}{d x} = 2 x y^{2}, y = - 1, x = 1

y^{^{'}} = 5 e^{x - y}

y(4-x^2)^{1/2}dy=(4+y^2)^{1/2}dx

y (4 - x^{2})^{\frac{1}{2}} d y = (4 + y^{2})^{\frac{1}{2}} d x

xy^'=ytan(ln(y))

x y^{^{'}} = y tan (ln (y))

Frequently Asked Questions (FAQ)

What is the solution for y^'=a(1-y) ?
The solution for y^'=a(1-y) is y=-e^{-at-c_{1}}+1