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Popular >

4y^'+6y=120,y(0)=1

Solution

4 y^{^{'}} + 6 y = 120, y (0) = 1

Solution

y = - 19 e^{- \frac{3 t}{2}} + 20

Solution steps

4 y^{'} (t) + 6 y = 120

Solve separable ODE:

y = - 19 e^{- \frac{3 t}{2}} + 20

y = - 19 e^{- \frac{3 t}{2}} + 20

Popular Examples

y^{^{'}} = 4 - y^{2}

2y^2y^'=3e^{2x}

2 y^{2} y^{^{'}} = 3 e^{2 x}

(dy)/(dx)=0.02y+40000,y(0)=2000000

\frac{d y}{d x} = 0.02 y + 40000, y (0) = 2000000

y(25-x^2)^{1/2}dy=(25+y^2)^{1/2}dx

y (25 - x^{2})^{\frac{1}{2}} d y = (25 + y^{2})^{\frac{1}{2}} d x

dy=2xye^{x^2}dx

d y = 2 x y e^{x^{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for 4y^'+6y=120,y(0)=1 ?
The solution for 4y^'+6y=120,y(0)=1 is y=-19e^{-(3t)/2}+20