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Popular >

y^'=3y+xy

Solution

y^{^{'}} = 3 y + x y

Solution

y = e^{3 x + \frac{x ^{2}}{2} + c_{1}}

Solution steps

y^{'} (x) = 3 y + x y

Solve separable ODE:

y = e^{3 x + \frac{x ^{2}}{2} + c_{1}}

y = e^{3 x + \frac{x ^{2}}{2} + c_{1}}

Popular Examples

(dy)/(dt)(t^2-16t+15)=y

\frac{d y}{d t} (t^{2} - 16 t + 15) = y

(dy)/(dx)=4x^3e^{-y}

\frac{d y}{d x} = 4 x^{3} e^{- y}

(y^')/(y^{1/2)}=-u

\frac{y ^{^{'}}}{y ^{\frac{1}{2}}} = - u

3(dy)/(dx)+2y=5

3 \frac{d y}{d x} + 2 y = 5

(dy)/(dx)=(y^2+y^2cos(x))^2

\frac{d y}{d x} = (y^{2} + y^{2} cos (x))^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'=3y+xy ?
The solution for y^'=3y+xy is y=e^{3x+(x^2)/2+c_{1}}