What is the solution for 3(dy)/(dx)+2y=5 ?

The solution for 3(dy)/(dx)+2y=5 is y=-(e^{(-2x-c_{1})/3})/(2)+5/2

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3(dy)/(dx)+2y=5

3 \frac{d y}{d x} + 2 y = 5

y = - \frac{e ^{\frac{- 2 x - c _{1}}{3}}}{2} + \frac{5}{2}

Solution steps

3 \frac{d y}{d x} + 2 y = 5

Solve separable ODE:

y = - \frac{e ^{\frac{- 2 x - c _{1}}{3}}}{2} + \frac{5}{2}

y = - \frac{e ^{\frac{- 2 x - c _{1}}{3}}}{2} + \frac{5}{2}

\frac{d y}{d x} = (y^{2} + y^{2} cos (x))^{2}

y^{^{'}} = - 3 y^{\frac{4}{3}} sin (t)

\frac{d y}{d x} = \frac{x + 1}{e ^{y}}

\frac{d y}{d x} = - \frac{8}{9} x^{2} y^{6}

y^{^{'}} = (\frac{2}{x} - x) y

What is the solution for 3(dy)/(dx)+2y=5 ?
The solution for 3(dy)/(dx)+2y=5 is y=-(e^{(-2x-c_{1})/3})/(2)+5/2