What is the solution for (dy)/(dx)=xy^2,y(2)=-2/5 ?

The solution for (dy)/(dx)=xy^2,y(2)=-2/5 is y=-2/(x^2+1)

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(dy)/(dx)=xy^2,y(2)=-2/5

\frac{d y}{d x} = x y^{2}, y (2) = - \frac{2}{5}

y = - \frac{2}{x ^{2} + 1}

Solution steps

\frac{d y}{d x} = x y^{2}

Solve separable ODE:

y = - \frac{2}{x ^{2} + 1}

y = - \frac{2}{x ^{2} + 1}

10 y^{^{'}} + 4 y = 3

\frac{d x}{d t} = 0.04 x + 5000

\frac{d}{d x} ((y - 3)^{2}) = 4 (x - 5)

y^{^{'}} = y t^{2} - 1.1 y

x \frac{d y}{d x} = e^{3 y + x}, x > 0

What is the solution for (dy)/(dx)=xy^2,y(2)=-2/5 ?
The solution for (dy)/(dx)=xy^2,y(2)=-2/5 is y=-2/(x^2+1)