What is the solution for (dy)/(dt)+4y=5,y(0)=1 ?

The solution for (dy)/(dt)+4y=5,y(0)=1 is y=-(e^{-4t})/4+5/4

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(dy)/(dt)+4y=5,y(0)=1

\frac{d y}{d t} + 4 y = 5, y (0) = 1

y = - \frac{e ^{- 4 t}}{4} + \frac{5}{4}

Solution steps

\frac{d y}{d t} + 4 y = 5

Solve separable ODE:

y = - \frac{e ^{- 4 t}}{4} + \frac{5}{4}

y = - \frac{e ^{- 4 t}}{4} + \frac{5}{4}

\frac{d y}{d x} = c_{1} y + 1

\frac{d v}{d t} = g - k v (t), v = 0, t = 0

\frac{d y}{d x} + 2 y = 11

\frac{d y}{d x} y = e^{x^{2 l n (x)}}

x^{^{'}} = (x)^{45 + 2} (ln (t) + (2 + 2) t e^{t})

What is the solution for (dy)/(dt)+4y=5,y(0)=1 ?
The solution for (dy)/(dt)+4y=5,y(0)=1 is y=-(e^{-4t})/4+5/4