What is the solution for 2xdx+2ydy=0 ?

The solution for 2xdx+2ydy=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2xdx+2ydy=0

2 x d x + 2 y d y = 0

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

Solution steps

2 x d x + 2 y d y = 0

Solve separable ODE:

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

x^{2} (x d y + y d x) = 9 x d y - 9 y d x

\frac{d y}{d x} + 8 y = 0

\frac{\frac{d y}{d x}}{y} = x^{x - 1}

y^{^{'}} + 2 y = 2, 6 sin (3 t) y (0) = 3

3 x \frac{d y}{d x} + 9 x^{3} y = 3 x^{3}

What is the solution for 2xdx+2ydy=0 ?
The solution for 2xdx+2ydy=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}