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Popular >

y^'+y/x = 2/x

Solution

y^{^{'}} + \frac{y}{x} = \frac{2}{x}

Solution

y = \frac{c _{1}}{x} + 2

Solution steps

y^{'} (x) + \frac{y}{x} = \frac{2}{x}

Solve separable ODE:

y = \frac{c _{1}}{x} + 2

y = \frac{c _{1}}{x} + 2

Popular Examples

y^3(dy)/(dx)=4x^3y^4-16x^3

y^{3} \frac{d y}{d x} = 4 x^{3} y^{4} - 16 x^{3}

y^'=-0.06sqrt(y)

y^{^{'}} = - 0.06 y

(dy)/(dx)=(x^2-1)/(y^2-1),y(2)=2

\frac{d y}{d x} = \frac{x ^{2} - 1}{y ^{2} - 1}, y (2) = 2

y^{^{'}} = 7 y, y (0) = 1

f(x)=x^5cos(x)f^'(x)

f (x) = x^{5} cos (x) f^{^{'}} (x)

Frequently Asked Questions (FAQ)

What is the solution for y^'+y/x = 2/x ?
The solution for y^'+y/x = 2/x is y=(c_{1})/x+2