What is the solution for (x+1)dy-3ydx=0 ?

The solution for (x+1)dy-3ydx=0 is y=e^{c_{1}}x^3+3e^{c_{1}}x^2+3e^{c_{1}}x+e^{c_{1}}

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(x+1)dy-3ydx=0

(x + 1) d y - 3 y d x = 0

y = e^{c_{1}} x^{3} + 3 e^{c_{1}} x^{2} + 3 e^{c_{1}} x + e^{c_{1}}

Solution steps

(x + 1) d y - 3 y d x = 0

Solve separable ODE:

y = e^{c_{1}} x^{3} + 3 e^{c_{1}} x^{2} + 3 e^{c_{1}} x + e^{c_{1}}

y = e^{c_{1}} x^{3} + 3 e^{c_{1}} x^{2} + 3 e^{c_{1}} x + e^{c_{1}}

y^{^{'}} - \frac{x sin ( x )}{3 y ^{2}} = 0, y (0) = 2

u^{^{'}} = e^{4 x - H (x)}

\frac{d y}{d x} + 2 x y = 2 x, y (0) = 2

\frac{d y}{d x} + 5 y = 20, y (0) = 2

\frac{d y}{d x} = \frac{- x + x y ^{2}}{y + x ^{2} y}

What is the solution for (x+1)dy-3ydx=0 ?
The solution for (x+1)dy-3ydx=0 is y=e^{c_{1}}x^3+3e^{c_{1}}x^2+3e^{c_{1}}x+e^{c_{1}}