What is the solution for (dx)/(dt)=x^2+1/81 ?

The solution for (dx)/(dt)=x^2+1/81 is x=(tan((t+c_{1})/9))/(9)

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(dx)/(dt)=x^2+1/81

\frac{d x}{d t} = x^{2} + \frac{1}{81}

x = \frac{tan ( \frac{t + c _{1}}{9} )}{9}

Solution steps

\frac{d x}{d t} = x^{2} + \frac{1}{81}

Solve separable ODE:

x = \frac{tan ( \frac{t + c _{1}}{9} )}{9}

x = \frac{tan ( \frac{t + c _{1}}{9} )}{9}

\frac{d x}{d t} = 0.36 - \frac{9 x}{100}

u^{^{'}} = x^{2} H (x)

\frac{d y}{d x} = - \frac{3 x + 3 x y ^{2}}{y x ^{2} + 2 y}

\frac{( d y )}{( d x )} = (2 x + 10) \cdot e^{- y}, y (0) = 0

g = \frac{d v}{d t} + v^{2} k

What is the solution for (dx)/(dt)=x^2+1/81 ?
The solution for (dx)/(dt)=x^2+1/81 is x=(tan((t+c_{1})/9))/(9)