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Popular >

xy^'+y-6=0

Solution

x y^{^{'}} + y - 6 = 0

Solution

y = \frac{c _{1}}{x} + 6

Solution steps

x y^{'} (x) + y - 6 = 0

Solve separable ODE:

y = \frac{c _{1}}{x} + 6

y = \frac{c _{1}}{x} + 6

Popular Examples

y^'=(x^2-5)/(y^2),y(0)=3

y^{^{'}} = \frac{x ^{2} - 5}{y ^{2}}, y (0) = 3

x^'=(x)^{22}(ln(t)+(10)+te^t)

x^{^{'}} = (x)^{22} (ln (t) + (10) + t e^{t})

y^{^{'}} = x y - x - y + 1

y^{^{'}} + \frac{1}{2} y = \frac{5}{2}

f(x)(g(x))f^'(x)=1+(f(x))^2

f (x) (g (x)) f^{^{'}} (x) = 1 + (f (x))^{2}

Frequently Asked Questions (FAQ)

What is the solution for xy^'+y-6=0 ?
The solution for xy^'+y-6=0 is y=(c_{1})/x+6