What is the solution for x^'=(x)^{22}(ln(t)+(10)+te^t) ?

The solution for x^'=(x)^{22}(ln(t)+(10)+te^t) is x=-\sqrt[21]{1/(21(tln(t)+9t+e^tt-e^t+c_{1))}}

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x^'=(x)^{22}(ln(t)+(10)+te^t)

x^{^{'}} = (x)^{22} (ln (t) + (10) + t e^{t})

Solution steps

x^{'} (t) = (x)^{22} (ln (t) + (10) + t e^{t})

Solve separable ODE:

y^{^{'}} = x y - x - y + 1

y^{^{'}} + \frac{1}{2} y = \frac{5}{2}

f (x) (g (x)) f^{^{'}} (x) = 1 + (f (x))^{2}

y^{- 1} d y - y e^{c o s (x)} sin (x) d x = 0

d y - d x (y - 1)^{2} = 0

What is the solution for x^'=(x)^{22}(ln(t)+(10)+te^t) ?
The solution for x^'=(x)^{22}(ln(t)+(10)+te^t) is x=-\sqrt[21]{1/(21(tln(t)+9t+e^tt-e^t+c_{1))}}