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Popular >

y^'=-2-y

Solution

y^{^{'}} = - 2 - y

Solution

y = e^{- t - c_{1}} - 2

Solution steps

y^{'} (t) = - 2 - y

Solve separable ODE:

y = e^{- t - c_{1}} - 2

y = e^{- t - c_{1}} - 2

Popular Examples

xcos(x)=(2y+e^{3y})y^'(x),y(0)=0

x cos (x) = (2 y + e^{3 y}) y^{^{'}} (x), y (0) = 0

(dy)/(dx)+9xy=4x,y(0)=5

\frac{d y}{d x} + 9 x y = 4 x, y (0) = 5

(dy)/(dx)y=(sin^2(pi-x))

\frac{d y}{d x} y = (sin^{2} (π - x))

(dP)/(dt)=0.0017P(1-P/(6200))

\frac{d P}{d t} = 0.0017 P (1 - \frac{P}{6200})

(dy)/(dx)+15x^2y=2x^2,y(0)=3

\frac{d y}{d x} + 15 x^{2} y = 2 x^{2}, y (0) = 3

Frequently Asked Questions (FAQ)

What is the solution for y^'=-2-y ?
The solution for y^'=-2-y is y=e^{-t-c_{1}}-2