What is the solution for (dt)/(dx)+3/x =-1/(x^2) ?

The solution for (dt)/(dx)+3/x =-1/(x^2) is x= 1/(3\W((1){3e^{\frac{-t+c_{1})/3}})}

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(dt)/(dx)+3/x =-1/(x^2)

\frac{d t}{d x} + \frac{3}{x} = - \frac{1}{x ^{2}}

x = \frac{1}{3 W ( \frac{1}{3 e ^{\frac{- t + c _{1}}{3}}} )}

Solution steps

\frac{d}{d x} (t) + \frac{3}{x} = - \frac{1}{x ^{2}}

Solve separable ODE:

x = \frac{1}{3 W ( \frac{1}{3 e ^{\frac{- t + c _{1}}{3}}} )}

x = \frac{1}{3 W ( \frac{1}{3 e ^{\frac{- t + c _{1}}{3}}} )}

\frac{d y}{d x} = 0.06 - \frac{y}{1350}

y^{^{'}} - 5 y = 10, y (0) = 0

f^{^{'}} (p) - f (p) = 0

((e^{3 x} + 3) e^{y}) d y - ((e^{y} - 4) e^{3 x}) d x = 0

\frac{d y}{d x} y = (6 x - 4)^{3}

What is the solution for (dt)/(dx)+3/x =-1/(x^2) ?
The solution for (dt)/(dx)+3/x =-1/(x^2) is x= 1/(3\W((1){3e^{\frac{-t+c_{1})/3}})}