en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1/x y^'-y-1=0

Solution

\frac{1}{x} y^{^{'}} - y - 1 = 0

Solution

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

Solution steps

\frac{1}{x} y^{'} (x) - y - 1 = 0

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

Popular Examples

y^'-2y=10,y(0)=0

y^{^{'}} - 2 y = 10, y (0) = 0

y^2sec(4x)(dy)/(dx)=1,y(0)=0

y^{2} sec (4 x) \frac{d y}{d x} = 1, y (0) = 0

y^'sin(y)+xcos(y)+x=0

y^{^{'}} sin (y) + x cos (y) + x = 0

y^'=(x+xy)/(1+x^2)

y^{^{'}} = \frac{x + x y}{1 + x ^{2}}

(dy)/(dx)x^2+2x^2y+3xy=0

\frac{d y}{d x} x^{2} + 2 x^{2} y + 3 x y = 0

Frequently Asked Questions (FAQ)

What is the solution for 1/x y^'-y-1=0 ?
The solution for 1/x y^'-y-1=0 is y=e^{(x^2)/2+c_{1}}-1