What is the integral of 2/(1-x) ?

The integral of 2/(1-x) is -2ln|1-x|+C

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integral of 2/(1-x)

\int \frac{2}{1 - x} d x

- 2 ln ∣ 1 - x ∣ + C

Solution steps

\int \frac{2}{1 - x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{1 - x} d x

Apply u-substitution

: \int - \frac{1}{u} d u

= 2 \cdot \int - \frac{1}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 (- \int \frac{1}{u} d u)

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 2 (- ln ∣ u ∣)

Substitute back

u = 1 - x

= 2 (- ln ∣ 1 - x ∣)

Simplify

= - 2 ln ∣ 1 - x ∣

Add a constant to the solution

= - 2 ln ∣ 1 - x ∣ + C

y^{^{'}} - y = x + 1

\frac{2 s}{s ^{2} - 8 s + 6}

\frac{d}{d x} (x^{\frac{l n ( 2 )}{( 1 + l n ( x ) )}})

f (x) = 12 (x - (\frac{1}{x}))^{4}, at x = 2